Let us consider the following bodies: { indent=4mm \item{‒} $X$ is a filled right circular cylinder of radius 1 about the $x$-axis. \item{‒} $Y$ is a similar cylinder about the $y$-axis. \item{‒} $Z$ is a similar cylinder about the $z$-axis. \item{‒} $R=X\cap Y$ and $S=X\cap Y\cap Z$. \item{‒} $U$ is the filled right isosceles triangular cylinder with side 1 given by the inequalities $z\geq 0$, $z\leq y$ and $y\leq 1$. \item{‒} $H=U\cap Z$ (the so-called “hoof”). \item{‒} $V$ is the filled right isosceles triangular cylinder with side 1 given by the inequalities $z\geq 0$, $z\leq x$ and $x\leq 1$. \item{‒} $J=U\cap V\cap Z$. } In this paper the author uses Cavalieri’s principle to compute rigorously the following volumes: { indent=6mm \item {(1)} vol$(R)=16/3$. \item {(2)} vol$(S)=16-8\sqrt{2}$. \item {(3)} vol$(H)=2/3$. \item {(4)} vol$(J)=(2-\sqrt{2})/3$. } Bodies $R$ and $H$ both appear in Archimedes’ method where, obviously, different techniques are used to compute their volume. The volume of $S$ and $H$ are presented here as generalizations of the previous ones using Cavalieri’s principle.

Reviewer:

Antonio M. Oller (Zaragoza)