<?xml version="1.0" encoding="utf-8"?>
<zbml>
  <query>an:05702421</query>
  <answers from="1" to="1" total="1">
  <rec>
    <an>Zbl 1195.46059</an>
    <au>Aramba\v si\'c, Ljiljana; Baki\'c, Damir; Raji\'c, Rajna</au>
    <ti>Finite-dimensional Hilbert $C^*$-modules.</ti>
    <la>EN</la>
    <so>Banach J. Math. Anal. 4, No. 2, 147-157, electronic only (2010).</so>
    <is>ISSN 1735-8787/e</is>
    <py>2010</py>
    <dt>J</dt>
    <cc>*46L08 46L05 46C50</cc>
    <ut>$C^*$-algebra; Hilbert $C^*$-module; (weakly) compact operator; finite-dimensional $C^*$-algebra; finite-dimensional Hilbert $C^*$-module</ut>
    <ab>In studying perturbations of the Wigner equation in inner product $C^*$-modules, {\it J. Chmieli\'nski, D. Ili\v sevi\'c, M. S. Moslehian} and {\it Gh. Sadeghi} [J. Math. Phys. 49, No. 3, 033519, 8 p. (2008; Zbl 1153.81342)] introduced the condition [H] stating that, for every bounded sequence $(v_n)$ in a Hilbert $C^*$-module $V$, there are a subsequence $(v_{n_k})$ of $(v_n)$ and $v\in V$ such that, for every $y\in V$, $\lim_{k\rightarrow\infty}\|\langle y,v_{n_k}\rangle -\langle y,v\rangle\|=0$. They proved that condition [H] is satisfied in every Hilbert $C^*$-module over a finite-dimensional $C^*$-algebra. Later, {\it Lj. Aramba\v si\'c, D. Baki\' c} and {\it M. S. Moslehian} [Oper. Matrices 3, No.~2, Article ID 14, 235--240 (2009; Zbl 1188.46036)] proved that, if a full Hilbert $A$-module satisfies condition [H], then $A$ must be finite-dimensional.? ? In the paper under review, the authors characterize the finite-dimensional Hilbert $C^*$-modules in terms of the convergence of certain sequences. More precisely, they prove that, if $V$ is a full right Hilbert module over a $C^*$-algebra $A$, then the following statements are mutually equivalent: (i) $V$ is finite-dimensional; (ii) $A$ and the $C^*$-algebra $K(V)$ of compact operators on $V$ are finite-dimensional; (iii) for every bounded sequence $(v_n)$ in $V$, there are a subsequence $(v_{n_k})$ of $(v_n)$ and $v\in V$ such that $\lim_{k\rightarrow\infty}\|v_{n_k}a-va\|=0$ $(a\in A)$ and $\lim_{k\rightarrow\infty}\|\langle y,v_{n_k}\rangle -\langle y,v\rangle\|=0$ $(y\in V)$; (iv) $K(V)$ is a unital $C^*$-algebra, and for every bounded sequence $(v_n)$ in $V$, there are a subsequence $(v_{n_k})$ of $(v_n)$ and $v\in V$ such that $\lim_{k\rightarrow\infty}\|\langle y,v_{n_k}\rangle -\langle y,v\rangle\|=0$ $(y\in V)$; (v) $A$ is a unital $C^*$-algebra, and for every bounded sequence $(v_n)$ in $V$, there are a subsequence $(v_{n_k})$ of $(v_n)$ and $v\in V$ such that $\lim_{k\rightarrow\infty}\|v_{n_k}a-va\|=0\,\,(a\in A)$.</ab>
    <rv>Mohammad Sal Moslehian (Mashhad)</rv>
    <ci>Zbl 1153.81342; Zbl 1188.46036</ci>
  </rec>
  </answers>
</zbml>

