Language:   Search:   Contact
World of
Mathematics
Database
»ZBMATH«
MSC 2000
MSC 2010
Reviewer
Service
Subscription
»ZBMATH«
ZBMATH Database | Advanced Search Print
Read more | Try MathML | Hide
Zentralblatt MATH has released its new interface!
For an improved author identification, see the new author database of ZBMATH.

ZBMATH Database Simple Search Advanced Search Command Search

Advanced Search

Query:
Fill in the form and click »Search«...
Format:
Display: entries per page entries
Zbl 0846.16034
Krishna Rao, M.Murali
$\Gamma$-semirings. I.
(English)
[J] Southeast Asian Bull. Math. 19, No. 1, 49-54 (1995). ISSN 0129-2021; ISSN 0219-175X/e

Let $M$ and $\Gamma$ be additive abelian semigroups with identity elements 0 and $0'$ respectively. If there exists a mapping $M\times\Gamma\times M\to M$ (images to be denoted $x\gamma y$, $x,y\in M$, $\gamma\in\Gamma$) satisfying for all $x, y, z\in M$, $\gamma,\mu\in\Gamma$: (a) $x\gamma (y\mu z)=(x\gamma y)\mu z$ (b) $x\gamma (y+z)=x\gamma y+x\gamma z$; $(x+y)\gamma z=x\gamma z+y\gamma z$; $x (\gamma+\mu) y=x\gamma y+x\mu y$ (c) $x\gamma 0=0\gamma x=x 0' y=0$ then $M$ is called a $\Gamma$-semiring. Numerous examples are given in the paper, and various concepts, analogous to those for semirings are defined. A $\Gamma$-semiring $M$ is called regular (resp. strongly regular) if for all $a\in M$ there exist $b_i\in M$, $\alpha_i,\beta_i\in\Gamma$ such that $a=\sum^n_{i =1} a\alpha_i b_i\beta_i a$ (resp. there exist $b\in M$, $\alpha,\beta\in\Gamma$ such that $a=a\alpha b\beta a$). The center of $M$ is the set $\{a\in M\mid a\alpha x=x\alpha a\ \forall x\in M,\ \alpha\in\Gamma\}$. An element $a$ of $M$ is nilpotent if for each $x\in M$, $\gamma\in\Gamma$, there exists $n\in\bbfN$ such that $(a\gamma)^n a=0$. $a$ is idempotent if there exists $\alpha\in\Gamma$ such $a=a\alpha a$. If $M$ is a $\Gamma$-semiring, the set $M_{mn}$ of $m\times n$ matrices with entries from $M$ is a $\Gamma_{nm}$-semiring with the natural operations of matrix addition and multiplication.\par The following results are proved: The center $B$ of a strongly regular $\Gamma$-semiring is a strongly regular sub $\Gamma$-semiring of $M$. Let $M$ be a strongly regular $\Gamma$-semiring. If all the idempotent elements of $M$ are in its center, then $M$ has no nonzero nilpotent elements. -- The matrix $\Gamma_{nm}$-semiring $M_{mn}$ is regular if and only if $M$ is a regular $\Gamma$-semiring.
[G.L.Booth (Unitra / Transkei)]
MSC 2000:
*16Y60 Semirings
16E50 Von Neumann regular rings and generalizations
16S50 Endomorphism rings: matrix rings

Keywords: center; $\Gamma$-semirings; strongly regular $\Gamma$-semirings; idempotent elements; nilpotent elements; matrix $\Gamma_{nm}$-semirings

Cited in: Zbl 1169.16033 Zbl 0921.16032

Login Username: Password:

Highlights
Scientific prize winners of the ICM 2010
Overhang
Lie groups, physics and geometry. An introduction for physicists, engineers and chemists.

Master Server

Zentralblatt MATH Berlin [Germany]

© FIZ Karlsruhe GmbH

Zentralblatt MATH master server is maintained by the Editorial Office in Berlin, Section Mathematics and Computer Science of FIZ Karlsruhe and is updated daily.

Other Mirror Sites



Copyright © 2013 Zentralblatt MATH | European Mathematical Society | FIZ Karlsruhe | Heidelberg Academy of Sciences
Published by Springer-Verlag | Webmaster