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<item>
  <id>03843736</id>
  <dt>j</dt>
  <an>03843736</an>
  <augroup>
    <au>Stob, Michael</au>
  </augroup>
  <ti>Index sets and degrees of unsolvability.</ti>
  <so>J. Symb. Log. 47, 241-248 (1982).</so>
  <py>1982</py>
  <pu>Association for Symbolic Logic, Poughkeepsie, NY</pu>
  <lagroup>
    <la>EN</la>
  </lagroup>
  <ccgroup>
  </ccgroup>
  <utgroup>
    <ut>index sets</ut>
    <ut>degrees of unsolvability</ut>
    <ut>simple sets</ut>
    <ut>priority argument</ut>
  </utgroup>
  <cigroup>
  </cigroup>
  <ligroup>
    <li>doi:10.2307/2273139</li>
  </ligroup>
  <abgroup>
    <ab>The paper's first main theorem was announced by Kallibekov; it refines a result of Yates. Let \b{C} and \b{D} be nonrecursive r.e. sets, \b{C} not of degree ${\cal O}'$, \b{C} recursive in \b{D}. Let \b{S} be any set in $\Sigma\sb 3(\underline D)$ (i.e., what follows the initial quantifiers is recursive in \b{D}). Then there exists a uniformly r.e. sequence of r.e. sets $\{$ \b{A}${}\sb{\underline j}\}$ such that \b{A}${}\sb{\underline j}$ has the same (Turing) degree as \b{D} whenever \b{j}$\in \underline S$, but has degree incomparable with that of \b{C} otherwise. The proof uses an infinite injury priority argument, a method discussed at some length. The paper's second main theorem strengthens a result of Kinber. Let \b{S} be a $\Sigma\sb 3$ set of indices of r.e. sets, none of which is infinite, coinfinite and recursive. Then there exists a nonrecursive r.e. set in which no nonrecursive set with index in \b{S} is recursive. An interesting corollary is that an r.e. set has supersets of every r.e. degree iff it is not simple.</ab>
    <rv>J.S.Ullian</rv>
  </abgroup>
</item>